Positive Essay Examples

positive feelings and acquaintances and to avoid pain. We are sensitive human beings; we are not in a position to choose what to feel, but people will always desire to be happier than sad or mad (Herschkopf, 2003). Because emotions are still accurate, people are always characterized to feel them all, but one thing to avoid is to compel them onto others thus the need to even be careful. Anger is an eminent and one useful listening and grasping or clinging to. Most of the times, it could be a message that we have been hurt our rights have been defined in some ways, our needs have not been suitably met or just that something is not right at all. When we choose to become perplexed by our anger or...

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positive which is the error of rejecting a null hypothesis when in fact it is true. False positive can also be described as accepting the alternative hypothesis when the findings are as a result of chance. A type I error takes place when one sees a statistically significant difference when in reality there is no difference. The likelihood of creating a type I error in a test with rejection region R is P (R | H0 is correct) (Mertler & Reinhart, 2016). On the other hand, type II error is called a false negative which is the error of accepting a null hypothesis when in fact it is false. A different definition of false negative is rejecting the alternative hypothesis when it is true. The type II...

positive value indicating that it is above the mean weight. If it had a negative value ,it implies that it is below the mean weight.( "Analysis of microarray data using Z score transformation Cheadle, Chris, et al 73-81 ."  From the z-score table P(Z=1.14)=0.8729. If 36 women were selected, the probability that their weight will lie between 140 and 211lb will be given by ; 0.8729x36=31.4244 CONCLUSION From the above two probabilities, the most relevant of the two will be the 0.8729.This is because a valid probability is always equal to 1 or less than zero. To be able to calculate the probabilities of the...

positives symptoms as her thoughts seem distorted from normal thinking and functioning. She demonstrates psychotic behaviours where most of the time she is unable to differentiate what is real from the imagined (Andreasen et al., 2012). As such, some of the common symptoms that she experiences include hallucinations whereby she hears or imagines that she is seeing people who are not present. Sydney experiences delusions since she believes in things that are not true. For instance, she claims that her brother used to fish for crappies when she was young but when she grew up, the crappies came back as people. Sydney also demonstrates thought disorders as most of her thoughts are quite unusual. Hence,...

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positive turn in activities towards effecting the crashing in the correct schedule, there would be efforts of supporting the team efforts using incentives. Comment Getting estimates on the regular timing as well as the crash time for each activity is a positive move as it would lead to guided choice of the way forward. However, in skipping the unnecessary steps in the activities, there would be a need for much carefulness as such moves could lead to shoddy work if there is no the right...

positive relationship between height and hand width. The relationship also seems to be linear since most plots are concentrated along the line running from left to right. The relationship seems to be strong since most plots are concentrated along the line with few values being further. The scatter plots show an increasing trend from left to right and hence a positive relationship can be identified between hand length and height. From the output, we can also see that the plots are concentrated along a lie indicating a linear relationship. Also, the plots show a weak relationship between hand length and height since more plots are scattered...

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positive gradient indicating that the variation is linear. The slope of the line is Young’s modulus, and for this case, it was calculated and found to be 10.3E6 (see the analysis), for aluminum. The other values that were calculated included: Shear Modulus of Elasticity (G), Applied Load (P), Bending Moment (M), and the Moment of Inertia (I). The summary of all these results is tabled as shown in the analysis sheet. In conclusion, strain Rosettes was used to measure the rotational and transverse strains for an aluminum beam under constant stress. The values of the Youngs modulus and other constants were found to be very close to the expected theoretical values. The little variations could be as a...

positive integer k that is for n=k, then for the case of n=k+1, we have (1+12)k+1=k+12Considering the LHS =(1+12)k(1+12)1≥(k+12)(1+12)1=32k+12=34(k+1)But k+1=n, therefore we have 34n. since (1+12)n≥34n, the inequality holds for both cases of n=k and n=k+1. It means that (1+12)n≥n2, for n ∈ N g. 11*. 2 +12*3+ 13*4+…+1nn+1=nn+1 Proof If n=1 then we have 11*2=11(1+1)Therefore the RHS = LHS and the proposition is true for n=1For n=k≥1, the equation becomes 11*2+12*3+13*4+…+1k*k+1=nk+1If n=k+1 then we have 11*2+12*3+13*4+…+1k*k+1+1k+1*k+2=kk+1+1k+1*k+2=k*k+2+1(k+1)*(k+2)=k2+2k+1(k+1)*(k+2)=(k+1)2(k+1)*(k+2)=(k+1)(k+2)By induction, the inequality holds true for both n=k and n=k+1 Workbook...

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positive therefore any change in beauty will influence an increment on course evaluation. The coefficient for the constant at 4.02936 is the value of course evaluation when beauty is zero. The coefficient on beauty is significant at 5% level since it has a p-value that is less than 0.05. c. STATA OUTPUT –Q c We run the regression with option 1 of onecredit omitted, since we want an indicative variable with classes not single credit represented by 0. The F-test is below 0.05 indicating that the model is statistically significant. The R-squared is 0.0629 which explains that 6.29% of the variance of course evaluation can be accounted for by the model. The t-tests for classes not single credit...

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positive and negative of 15) e. {a N | a <-4 and a >a} Solution:It is impossible to list the elements since they are infinite in number. “N” refers to natural numbers and therefore "-4" is irrelevant. 2. List five elements in each of the following sets: d. {nN|n2 + n is a multiple of 3} Solution:The numbers are in the form n2+n=3p for some integer P hence: n={3,5,6,8,9} 9a. List all the subsets of the set {a, b, c, d} that contain Solution i.) four elements - {a,b,c,d}ii.) three elements - {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}iii.) two elements - {a,b}, {a,c}, {a,d}, {b,c}, {b,d}, {c,d}iv.) one element - {a}, {b}, {c}, {d}v.) no elements - {0} Page 49 3. Let A = {(-1,2), (4, 5), (0, 0), (6,...

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