Rule Essay Samples and Topic Ideas

rule to get the second derivative =43ddxx-23+x13+x-23+x13ddx43=43(-23x-53+13x-23)f''x=-89x53+49x23d. The intervals on which the function increases or decreases and local minimum when the first derivative is equals to zero f' , 43x23+4x133=04x133x-1 +1=0 it follow that x =0 or-1Function decreases for x<-1 and -1<x<0Increases for x>0Local minimum x=0e. concave down or up for the function and sketch a graph f''x=-89x53+49x23 when f''x=0 therefore-492x-53-x-23=0 x=2by choosing x=0 and x=3 it follows that f''0=43>0 hence -∞,2 the curve is concave upward ) And f''3=integer hence 2, ∞ the curve is concave upward f. approximate intervals. i. increasing. x>1ii....

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Rule to Maximize Profitability.” Much Shelist. Accessed Frieswick. “Forging the Tools for Excellence.”, MEJ. "Power Laws, Pareto Distributions and Zipf's Law." Contemporary Physics. 46.5 (2005): 323-351. Print. Nichols Michele. “Applying the 80/20 Strategy in Advanced Manufacturing.” (April 13, 2017). Accessed (February 17, 2018) Chain Network Design. (ctober 17, 2012)...

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rule is used for differentiating compositions of functions. This happens when the function contains layers. The chain rule guides that we start with the outer layers leaving the inner layer untouched and then differentiate the inner layers while holding the outer layer. The final answer is the simplified. Question2 f(x) = cos (x4) f(x)=cosx4derivative of cos=-sin; hence dydx=4x3 where h=x4ddx(cos(h)).d/dx(h)=-sin(x4).4x3= -4x^3sinx4Question 3 G(x) = (cosx)4Let h=x ggx=4(cosx)3 .-sinx= -4〖(cos⁡x)〗^3 .sin⁡xQuestion 4 Implicit differentiation of x2+y2=8, at points (2,2) and (-2,2) On differentiating 2xddx+2yddy=ddx8Hence 2x+2yy’ =02x=-2yy’ meaning y’=-x/yAt (2,2) then y’=-22=-1;At (-2,2)...

rule. When confirming the calculated values with those measured using the necessary measuring equipment of measuring some differences was found in the values. These differences can be attributed to the issue of measuring errors that are usually common when humans are conducting experiments. The sources of errors in the circuit generally were due to the issue of reading and improper connections of the reading equipment leads to the circuit. Some of the values of read from the voltmeter were, however, tallying correctly with those calculated. The errors for table one were as below: For R1.165-2=0.165ohms, %error= 0.165/2*100=8.25%. For R2, 0.98-1=-0.02ohms, %error=-0.02/1*100=2%. For R3,...

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