Rule Essay Samples and Topic Ideas

Problem Solving

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rule to get the second derivative =43ddxx-23+x13+x-23+x13ddx43=43(-23x-53+13x-23)f''x=-89x53+49x23d. The intervals on which the function increases or decreases and local minimum when the first derivative is equals to zero f' , 43x23+4x133=04x133x-1 +1=0 it follow that x =0 or-1Function decreases for x<-1 and -1<x<0Increases for x>0Local minimum x=0e. concave down or up for the function and sketch a graph f''x=-89x53+49x23 when f''x=0 therefore-492x-53-x-23=0 x=2by choosing x=0 and x=3 it follows that f''0=43>0 hence -∞,2 the curve is concave upward ) And f''3=integer hence 2, ∞ the curve is concave upward f. approximate intervals. i. increasing. x>1ii....

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Couldn't find the right Rule essay sample? Management/Logistics

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Rule to Maximize Profitability.” Much Shelist. Accessed https://www.muchshelist.com/insights/article/qa-using-8020-rule-maximize-profitabilityKris Frieswick. “Forging the Tools for Excellence.” http://www.itw.com/wp-content/uploads/2012/12/043012_ITW100Years_KindleFire.pdfNewman, MEJ. "Power Laws, Pareto Distributions and Zipf's Law." Contemporary Physics. 46.5 (2005): 323-351. Print. Nichols Michele. “Applying the 80/20 Strategy in Advanced Manufacturing.” Lauchsolutions.com. (April 13, 2017). Accessed (February 17, 2018) http://www.launchsolutions.com/blog/applying-the-80-20-strategy-in-advanced-manufacturingSupply Chain Network Design. (ctober 17, 2012)...

• Words: 550
• Pages: 2

Mathematics

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rule is used for differentiating compositions of functions. This happens when the function contains layers. The chain rule guides that we start with the outer layers leaving the inner layer untouched and then differentiate the inner layers while holding the outer layer. The final answer is the simplified. Question2 f(x) = cos (x4) f(x)=cosx4derivative of cos=-sin; hence dydx=4x3 where h=x4ddx(cos(h)).d/dx(h)=-sin(x4).4x3= -4x^3sinx4Question 3 G(x) = (cosx)4Let h=x ggx=4(cosx)3 .-sinx= -4〖(cos⁡x)〗^3 .sin⁡xQuestion 4 Implicit differentiation of x2+y2=8, at points (2,2) and (-2,2) On differentiating 2xddx+2yddy=ddx8Hence 2x+2yy’ =02x=-2yy’ meaning y’=-x/yAt (2,2) then y’=-22=-1;At (-2,2)...

• Words: 275
• Pages: 1