Probability Essay Samples and Topic Ideas
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probability of attaining bn for each player would be 50%, Thus, at equilibrium, bn = ½ Suppose MMn chooses never to become informed (pn = 0), and MMm chooses always to become informed (pm = 1). Suppose the uninformed MM sets prices 0 < bn ≤ an < 1. Argue that in this case, the informed MM should optimally set bid (ask) price marginally above (below) the informed MM’s bid (ask) price whenever V = 1 (V = 0). As for the ask (bid) price when V = 1 (V = 0), any price such that the informed MM will not sell (buy) the asset is optimal. Price setting for MMn is bound by their comprehension of the market. In the case of MMn1 assuming ignorance of the value, the modelling of the pricing for both...
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probability that her weight is between 140lb-211lb will be as given below; We calculate the z- score for a row value between 140 and 211.To decide on the value, we can get the average of the two values as shown below; Average of 140 and 211= 140+211=351/2=175.5=176. Z-SCORE FOR 176= 176-143=33/29= 1.13793=1.14 Z-score = Row score – Mean Standard Deviation The z-score obtained has a positive value indicating that it is above the mean weight. If it had a negative value ,it implies that it is...
- Words: 275
- Pages: 1
probability that to fall within the range specified. This illustrates the significance of confidence interval; therefore, a confidence interval can be described as a parameter in statistics used to describe an amount of uncertainty associated with a given sample estimation of a population. When analyzing statistical results of a research study confidence interval is imperative in providing a report. In most cases when a research study is carried out it may involve a large population with a range of outcome on a particular variable, and in this case, it is only possible to average the result over a given interval. For example, after a research study on time spent on leisure activities of 2000...
- Words: 275
- Pages: 1
probability that 2 customers will arrive the next three hours? Solution: The probability of only 2 customers arriving is given by; P(X) = e-uux/x!Where x = 2 e = 2.71828 u= mean number of successes in the specified region of space u=4*3=12 Hence P (2) = e-12122/2! =...
- Words: 1100
- Pages: 4
probability, impact, and resources in the case of the risk analysis worksheet. Further, the risk analysis worksheet does not offer a better scale for determining the risk level....
- Words: 275
- Pages: 1